In standard notation "\\theta" is the zenith angle, so it changes from 0 to "\\pi" . Let us first determine the total charge of the sphere. If the total charge is not equal to zero, the monopole term of the potential will not be zeroth, so it will determine the main part of the potential.
"Q_{\\text{total}} = \\int\\limits_{0}^{2\\pi}\\int\\limits_0^{\\pi} (\\sigma_0 \\sin\\theta)\\cdot R^2\\sin\\theta\\, d\\theta d\\phi = 2\\pi \\sigma_0 R^2 \\int\\limits_0^{\\pi} \\sin^2\\theta \\,d\\theta= 2\\pi \\sigma_0 R^2 \\cdot \\dfrac{\\pi}{2} = \\pi^2 \\sigma_0 R^2."
We see that the total charge is not equal to 0, so in the multipole expansion the monopole term will not be zeroth. Therefore, the monopole term is proportional to "\\dfrac{Q_{\\text{total}}}{r}" and the total potential will be approximately proportional to 1/r
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