As per the given question,
Total number of particle =N
Total energy of the system=?
We know that, En=Nπ2ℏ28mLE_n=\frac{N\pi^2\hbar^2}{8mL}En=8mLNπ2ℏ2
As per the question, n=2,
Hence,
E2=Nπ2ℏ24mLE_2=\frac{N\pi^2\hbar^2}{4mL}E2=4mLNπ2ℏ2
Hence, Fermi energy, here, n=N2n=\frac{N}{2}n=2N
EF=ℏ28π2m(nπL)2E_F=\frac{\hbar^2}{8\pi^2m}(\frac{n\pi}{L})^2EF=8π2mℏ2(Lnπ)2
EF=ℏ28π2m(N2L)2E_F=\frac{\hbar^2}{8\pi^2m}(\frac{N}{2L})^2EF=8π2mℏ2(2LN)2
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