Answer to Question #126050 in Electricity and Magnetism for arep

Question

Figure 5 shows two conducting rails 0.500 m apart with a 50.0 g conducting bar that slides on top of two rails. A magnetic field of 0.750 T is directed perpendicular to the plane of the rails and points upward. An external dry cell is connected to the rails supplying a voltage, V and a constant current of 1.00 A to the rail-bar system.

Answer 1

As we know that

F= $ILBsin\theta$

$\theta= 90^o$ ( since they are perpendicular)

so F = $ILB$

acceleration (a) = F/m

a =$ILB/m$ ;m= 0.05kg

a= 1*0.500*0.750/0.05

a= 7.5m/s²

speed of conductor can be calculated as

v = √(2as)