Write all forces by their axes along which the acceleration is directed according to Newton's second law:
"\\text{Block: }m_2a=m_2g\\text{ sin}\\theta-T,\\\\\n\\text{Ball: }m_1a=T-m_1g." Divide one by another:
"\\frac{m_2}{m_1}=\\frac{m_2g\\text{ sin}\\theta-T}{T-m_1g},\\\\\n\\space\\\\\nT=g\\cdot\\frac{m_1m_2(1+\\text{sin}\\theta)}{m_1+m_2}." Acceleration, on the other hand, will be
"a=\\frac{T}{m_1}-g,\\\\\n\\space\\\\\na=g\\bigg[\\frac{m_2(1+\\text{sin}\\theta)}{m_1+m_2}-1\\bigg],\\\\\n\\space\\\\\na=g\\cdot\\frac{m_2\\text{ sin}\\theta-m_1}{m_1+m_2}."
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