Question #102353

A ball of mass m1 and a block of mass m2 are attached by a lightweight cord that passes

over a frictionless pulley of negligible mass, as in figure below. The block lies on a frictionless incline of

angle θ. Find the magnitude of the acceleration of the two objects and the tension in the cord.

Expert's answer


Write all forces by their axes along which the acceleration is directed according to Newton's second law:


Block: m2a=m2g sinθ−T,Ball: m1a=T−m1g.\text{Block: }m_2a=m_2g\text{ sin}\theta-T,\\ \text{Ball: }m_1a=T-m_1g.

Divide one by another:


m2m1=m2g sinθ−TT−m1g, T=g⋅m1m2(1+sinθ)m1+m2.\frac{m_2}{m_1}=\frac{m_2g\text{ sin}\theta-T}{T-m_1g},\\ \space\\ T=g\cdot\frac{m_1m_2(1+\text{sin}\theta)}{m_1+m_2}.

Acceleration, on the other hand, will be


a=Tm1−g, a=g[m2(1+sinθ)m1+m2−1], a=g⋅m2 sinθ−m1m1+m2.a=\frac{T}{m_1}-g,\\ \space\\ a=g\bigg[\frac{m_2(1+\text{sin}\theta)}{m_1+m_2}-1\bigg],\\ \space\\ a=g\cdot\frac{m_2\text{ sin}\theta-m_1}{m_1+m_2}.
LATEST TUTORIALS
APPROVED BY CLIENTS