A wire of total length 5.00 m, consists of equal lengths of Cu followed by Al, both having the same diameter of 1.00 mm. A voltage difference of 89.0 V is placed across the composite wire. What is the current flowing in the wire? Use rho=1.72x10-8 ohm-m for the resistivity of copper and rho=2.82x10-8 ohm-m for the resistivity of aluminum.
1
Expert's answer
2012-02-14T12:04:07-0500
We can imagine two pieces of wire as two resistors - Aluminum and Cuprum. Then the sum of this resistances will give us the necessary resistance R. R=R1+R1=rho(cu)xl(cu)/S(cu)+rho(al)xl(al)/S(al)={l(cu)=l(al)=l/2, S(cu)=S(al)=pi*(d/2)^2}=(1,72+2,82) x 10^(-8)omh*m x 2.5m/(0.78 x 10^(-6)m)=0,1445Omh; I=U/R=89V/0,1445Omh=615.86A
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment