Answer to Question #321347 in Electric Circuits for Jean Salak

Question #321347

A 32.0-Ω resistor and a 20.0-Ω are connected in parallel, and the combination is applied



across a 240 V dc line.



(a) What is the resistance of the parallel combination?



(b) What is the total current through the parallel combination?



(c) What is the current through each resistor?




1
Expert's answer
2022-05-04T12:40:29-0400

a) Resistance of the parallel combination:

R=R1R2R1+R2=32.020.032.0+20.012.3(Ohm)R = \cfrac{R1*R2}{R1+R2} = \cfrac{32.0*20.0}{32.0+20.0} \approx 12.3 (Ohm)



b) Total current through the parallel combination

I=VR=24012.319.5(A)I = \cfrac{V}{R} = \cfrac{240}{ 12.3} \approx 19.5 (A)



c) Current through each resistor

I1=VR1=24032.0=7.5(A)I2=VR2=24020.0=12(A)I1 = \cfrac{V}{R1} = \cfrac{240}{32.0} = 7.5 (A)\\ I2 = \cfrac{V}{R2} = \cfrac{240}{20.0} = 12 (A)



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