A cylindrical rod has resistance R. If we triple its length and diameter, what is the resistance, in terms of R?
Resistance of rod:
R=ρ⋅4lπ⋅d2R=\rho\cdot\frac{4l}{\pi\cdot d^2}R=ρ⋅π⋅d24l
Answer the resistance is R/3
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