Question #311272

A typical incandescent bulb has an efficiency of about 10%. What current is needed for a bulb with a resistance of 1.5×10^2 Ω to output power of 6.0 W?


1
Expert's answer
2022-03-15T16:50:04-0400

Explanations & Calculations


  • Working power of the bulb

P=6.0W×10010=60.0W\qquad\qquad \begin{aligned} \small P&=\small 6.0\,W\times\frac{100}{10}=60.0\,W \end{aligned}

  • The the current consumed at that power would be

P=I2RI=60.0W1.5×102Ω=6.3×101A\qquad\qquad \begin{aligned} \small P&=\small I^2R\\ \small I &=\small \sqrt{\frac{60.0\,W}{1.5\times10^2\, \Omega}}= 6.3\times10^{-1}\,A \end{aligned}


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