Two heating elements which is 500 ohms and 250 ohms are connected in series with temperature coefficients of 0.001 and 0.003 ohms per °C, respectively at 20°C. Calculate the effective temperature coefficient of the combination.
Resistance at t=0 °C
"R_0=R_T (1- \u03b1_TT) \\\\\n\nR_0(500 \\; \\Omega) = 500(1-0.001 \\times 20) = 490 \\; \\Omega \\\\\n\nR_0(250 \\; \\Omega) = 250(1 -0.003 \\times 20) = 235 \\; \\Omega \\\\\n\n(490 + 235) = (500+250)(1-\u03b1_T \\times 20) \\\\\n\n725 = 750(1 -20\u03b1_T) \\\\\n\n1-20\u03b1_T = 0.9667 \\\\\n\n\u03b1_T = \\frac{0.0333}{20} = 0.00167"
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