A dc shunt motor after running for several hours on constant voltage mains of 400 V takes a field current of 1.6 A. If the temperature rise is known to be 40°C, what value of extra circuit resistance is required to adjust the field current to 1.6 A when starting from cold at 20°C? Temperature coefficient = 0.0043/°C at 20°C.
resistance:
"R=R_{40}(1+\\alpha(T-40))"
resistance for 40°C:
"R_{40}=400\/1.6=250\\ \\Omega"
then resistance at 20°C:
"R=250(1+0.0043(20-40))=228.5\\ \\Omega"
so, value of extra circuit resistance:
"250-228.5=21.5\\ \\Omega"
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