Question #241349
the substation bus bar is made up of 2-inches round copper bars, 20- feet long. what is the resistance of each bar if the resistivity is 1.7241 x 10 -6 ω-cm.
1
Expert's answer
2021-09-26T21:01:39-0400

Length (l)=203.281=6.096m\frac{20}{3.281}=6.096m

r=2×0.0254=0.0508m2\times0.0254=0.0508m

R=ρlAR=\frac{\rho l}{A}

Put value

A=π(0.0508)2=8.11×103m2A=\pi(0.0508)^2=8.11\times10^{-3}m^2

ρ=1.7241×108Ω×m\rho=1.7241\times10^{-8}\Omega\times m

R=ρlAR=\frac{\rho l}{A}



R=1.7241×108×6.0963.14×0.05082R=1.7241×108×6.0968.11×103=5.185×105ΩR=\frac{1.7241\times10^{-8}\times6.096}{3.14\times0.0508^2}\\R=\frac{1.7241\times10^{-8}\times6.096}{8.11\times10^{-3}}=5.185\times10^{-5}\Omega


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