Question #241063

In a household during a particular week three 2kW fires are used on average 25h each and eight 100W light bulbs are used on average 35h each.Determine the cost of electricity for the week if 1 unit of electricity costs 15p.

Expert's answer

First, we have to calculate the energy consumed in total and it has to be expressed in kWh, thus the consumption of the light bulb will be 100 W=0.100 kW, then we find:


Power consumed=(3fires)(2kWfire)(25h)+(8bulbs)(0.100kWbulb)(35h)Power consumed=(6×25+7×4)kWh=(150+28)kWh=178kWh\text{Power consumed}=(3\,fires)(2\frac{kW}{fire})(25\,h)+(8\,bulbs)(0.100\frac{kW}{bulb})(35\,h) \\ \text{Power consumed}={(6\times25+7\times4)}\,kWh={(150+28)}\,kWh=178\,kWh


After that, we can calculate the total cost by just multiplying two factors:


Cost of electricity=(178kWh)(15pkWh)=2670p\\ \text{Cost of electricity}=(178\,\cancel{kWh})\Large{(\frac{15p}{\cancel{kWh}})}=2670\,p


In conclusion, the total cost of electricity will be 2670 p.
Reference:

  • Sears, F. W., & Zemansky, M. W. (1973). University physics.

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