First, we have to calculate the energy consumed in total and it has to be expressed in kWh, thus the consumption of the light bulb will be 100 W=0.100 kW, then we find:
"\\text{Power consumed}=(3\\,fires)(2\\frac{kW}{fire})(25\\,h)+(8\\,bulbs)(0.100\\frac{kW}{bulb})(35\\,h)\n\\\\ \\text{Power consumed}={(6\\times25+7\\times4)}\\,kWh={(150+28)}\\,kWh=178\\,kWh"
After that, we can calculate the total cost by just multiplying two factors:
"\\\\ \\text{Cost of electricity}=(178\\,\\cancel{kWh})\\Large{(\\frac{15p}{\\cancel{kWh}})}=2670\\,p"
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