Resistance,R=V/A=240/1.5=160ΩResistance, R=V/A=240/1.5=160\OmegaResistance,R=V/A=240/1.5=160Ω
calculate inductance L
at resonance XL=XC=RX_L=X_C=RXL=XC=R
So XL=2πfLX_L=2\pi fLXL=2πfL
R=2πfLR=2\pi fLR=2πfL
L=R2πf=1602×π×50=0.5093HL=\frac{R}{2\pi f}=\frac{160}{2\times \pi \times 50}=0.5093HL=2πfR=2×π×50160=0.5093H
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