Question #186079

Three 30-ohm resistors are connected in parallel across a 60 – volt source.

   a) What is the effective resistance of the circuit?

 

 

 

 

 

   b) Find the total current drawn from the source.

 

 

 

 

 

   c) Find the current through each resistor.

 



1
Expert's answer
2021-04-30T11:26:30-0400

1RT=130+130+130=110=0.1\frac{1}{R_T} = \frac {1}{30} + \frac {1}{30} + \frac {1}{30} = \frac{1}{10} = 0.1

RT=10.1=10ohmsR_T =\frac{1}{0.1} = 10ohms


b.)I=VRI =\frac {V}{R}

Where

V= Voltage

R= Resistance

I= current

I=6010=6AmpsI =\frac {60}{10}= 6Amps


c.) I=VRI =\frac {V}{R}

IR1=6030=2AIR_1 = \frac{60}{30} = 2A

IR2=6030=2AIR_2 = \frac{60}{30} =2A

IR3=6030=2AIR_3 = \frac{60}{30} = 2A

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS