Answer to Question #185433 in Electric Circuits for rose

Question #185433
a spark plug in an aoutomobile engine consists of two metal conductors that are separated by a distance of 0.5mm. When an electric spark jumps between them, the magnitude of the electric field is 4.0x107V/m. What is the magnitude of the potential difference V between the conductors?
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Expert's answer
2021-04-29T10:44:22-0400

Separation between plates, d=0.5 mm=0.5×103 md=0.5\space mm=0.5\times10^{-3}\space m

Electric field, E=4×107 V/mE=4\times10^7\space V/m

Electric field between two conducting plates, E=VdE=\dfrac{V}{d}

V=E.d=(4×107)×(0.5×103)=2×104 VV=E.d=(4\times10^7)\times(0.5\times10^{-3})=2\times10^4\space V


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Comments

Jaeno Co
31.05.21, 08:52

Thanks, it makes physics easy

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