Answer to Question #153410 in Electric Circuits for Wilder

Question #153410

Points A and B are 0.10 􀀄 apart. A point charge of +3.0 × 10-9C is placed at A and a point charge of

−1.0 × 10-9C is placed at B.

i) X is a point on the straight line through A and B, between A and B, where the electric potential is zero.

Calculate the distance AX.

ii) Show on a diagram the appropriate position of a point, Y, on the straight line through A and B where the field strength is zero.


1
Expert's answer
2021-01-10T18:31:39-0500

Answer

1) using direct short formula to calculate distance AX from point charge 3nC

x=qq+qr=33+1(10cm)x=\frac{\sqrt{q}}{\sqrt{q}+\sqrt{q'}}r=\frac{\sqrt{3}}{\sqrt{3}+\sqrt{1}}(10cm)

x=6cmx=6cm from point charge 3nC or called AX.

2) diagram can be shown as below


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