Points A and B are 0.10 apart. A point charge of +3.0 × 10-9C is placed at A and a point charge of
−1.0 × 10-9C is placed at B.
i) X is a point on the straight line through A and B, between A and B, where the electric potential is zero.
Calculate the distance AX.
ii) Show on a diagram the appropriate position of a point, Y, on the straight line through A and B where the field strength is zero.
Answer
1) using direct short formula to calculate distance AX from point charge 3nC
"x=\\frac{\\sqrt{q}}{\\sqrt{q}+\\sqrt{q'}}r=\\frac{\\sqrt{3}}{\\sqrt{3}+\\sqrt{1}}(10cm)"
"x=6cm" from point charge 3nC or called AX.
2) diagram can be shown as below
Comments
Leave a comment