Question #153107
The length of a metal wire is drawn and doubled. How many times will the new resistance of the wire become?
1
Expert's answer
2020-12-29T15:32:40-0500

We know that resistance of wire depend on its length and cross sectional area.Mathematically


R=ρlAR=\rho\frac{l}{A}

Where R is resistance of wire, l is length of wire ,A is cross sectional area and ρ\rho is resistivity of metal.

Note that after stretching wire its cross sectional area and length varies but Its volume(Al=constant)(Al=constant)remain constant.It means that If length is doubled , automatically its cross sectional area is halved. Thus New resistance of wire


Rnew=ρ2lA2R_{new}=\rho\frac{{2l}}{\frac{A}{2}}


Rnew=4ρlA=4RR_{new}=4\rho\frac{l}{A}=4R

Thus New resistance of wire is 4 times of the initial value.


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