A circuit consists of a 100 Ω resistor, a 5 V battery, and an LED placed correctly and all in series. The voltage drop across the LED is 2 V. What is the current through the LED?
1
Expert's answer
2012-09-06T09:59:05-0400
Total voltage drop is 5 V. So, the voltage drop across the resistor is Ur = 5 - 2 = 3 V. The current in a circuit is I = Iled = Ir = Ur / R = 3 / 100 = 0.03 A.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment