The resistance of a normal metal at a temperature of "0 \\degree - 100 \\degree" of Celsius changes directly in proportion to the temperature according to the linear law:
(1) "R=R_0\\cdot(1+\\alpha \\Delta T)" , where "R_0" - the resistance at an temperature "T_0", "\\alpha" - temperature coefficient of resistivity, and "\\Delta T=T-T_0" the difference between actual temperature and initial one. For copper in our task we have "R_0=2 \\Omega" , "\\alpha=0.00393 K^{-1}, \\Delta T_1=0\\degree C-100\\degree C=-100 K" . When calculating the temperature difference, we took into account that "1\\degree C=1K", but the absolute temperature values in these scales of temperature (Celsius and Kelvin) are very different [°C] = [K] − 273.15 [1].
To find resistance at "T=0\\degree C" we substitute these quantities to (1)
"R_1=R_0\\cdot(1+\\alpha \\Delta T_1)=2\\Omega\\cdot(1+0.00393 K^{-1}\\cdot (-100K))=2\\Omega\\cdot(1-0.393)=1.21\\Omega"
At a temperature "100 \\degree" higher ("T_2=200\\degree C" )we get "\\Delta T_2=200\\degree C- 100\\degree C=100K" and
"R_2=R_0\\cdot(1+\\alpha \\Delta T_2)=2\\Omega\\cdot(1+0.00393 K^{-1}\\cdot (100K))=2.79\\Omega"
Answer: If the resistance of a copper wire is "2\\Omega" at a temperature of "100 \\degree C", the resistance of the wire at "0\\degree C" will be "1.21\\Omega" and at "200 \\degree C" will be "2.79\\Omega" .
[1] https://en.wikipedia.org/wiki/Kelvin
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