Question #106625

Positive charge Q is placed on a conducting spherical shell of inner radius R1 outer radius R2.A particle with charge q is placed at center of cavity.The magnitude of electric field at a point from cavity at a distance r from center is?

Expert's answer

According to Gauss's theorem E×4×pi×r2=q×r3r0×R3E \times 4 \times pi \times r^{2} = \frac{q\times r^3}{r_0\times R^3}

E=q×r4π×R3×e0E=\frac{q\times r}{4 \pi \times R^3 \times e_0}


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