oils have dielectric constants that typically range from 2.1 to 2.4 lets assume this as 'k'
Capacitance hence will become 'kC' , where C is capacitance of the capacitor in air
So we have two capacitors one with capacitance 'kC' and the other one with the capacitance 'C'
As we know that "q=CV"
As the both the capacitance are carrying equal charges we can write it as
"CV_{air}=kCV_{oil }\\\\\\frac{V_{air}}{V_{oil}}=k"
As electric field in capacitor is given by the V/d and here d is same in both the capacitor
Hence the ratio of Electric field will be same as that of Voltage
"\\frac{E_{air}}{E_{oil}}=k"
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