We need to find the first integral of the equation
We can do it by two different ways, we choose the direct integration (the second way - using energy conservation)
Let's multiply the equation by "{\\dot r}"
and notice that
"\\mu \\ddot r\\dot r = \\frac{\\mu }{2}\\frac{d}{{dt}}({{\\dot r}^2})"then notice that
"- \\frac{k}{{{r^2}}}\\dot r = \\frac{d}{{dt}}(\\frac{k}{r})"
It means, that our equation can be rewritten as
And you can simply integrate it
Now "C" is some constant. We can use that in some point "r = R" (colled turning point) "\\dot r = 0" , we can use it to find "C"
Then just rewrite equation as
"\\frac{\\mu }{2}{{\\dot r}^2} = k(\\frac{1}{r} - \\frac{1}{R})"
We got what we wanted - the first integral.
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