Question #85710

A ball is made of a long string of thickness about 2 mm. The radius of the ball is 10 cm. Estimate the length of the string. Point out the possible errors in your calculation.
1

Expert's answer

2019-03-04T09:36:07-0500

Solution to #85710, Physics/Classical mechanics

Comparing the total volume occupied by the string with the volume of ball gives rise to relation as


L=4R3d2L = \frac {4 R ^ {3}}{d ^ {2}}


Where L is the length of string

R is the radius of ball=10cm=0.10m

d is the thickness of string=2mm=2/1000 m

Dimension should have same units


L=4R3d2L = \frac {4 R ^ {3}}{d ^ {2}}L=4(0.1)3(2/1000)2L = \frac {4 (0 . 1) ^ {3}}{\left(2 / 1 0 0 0\right) ^ {2}}L=0.0044(10)6L = \frac {0 . 0 0 4}{4 (1 0) ^ {- 6}}L=1000mL = 1 0 0 0 mL=1km\mathrm {L} = 1 \mathrm {k m}


Possible error: While deriving the formula

i) Calculation is based on assumption of ball is spherical

ii) It is possible that strings in the ball is not closely packed and have gaps between uncountable gaps between adjacent sections of the string

iii) The value of pie is assume as 3.00 but actual is 3.14

Answer provided by https://www.AssignmentExpert.com

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS