Solution to #85710, Physics/Classical mechanics
Comparing the total volume occupied by the string with the volume of ball gives rise to relation as
Where L is the length of string
R is the radius of ball=10cm=0.10m
d is the thickness of string=2mm=2/1000 m
Dimension should have same units
Possible error: While deriving the formula
i) Calculation is based on assumption of ball is spherical
ii) It is possible that strings in the ball is not closely packed and have gaps between uncountable gaps between adjacent sections of the string
iii) The value of pie is assume as 3.00 but actual is 3.14
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