Question #234858

Suppose that the force on a 1kg mass on the surface of the earth is 10N and that the radius of the earth is about 600 km. Then the force on an 8kg mass placed at a point 2000 km from the center of the earth will be?


1
Expert's answer
2021-09-08T16:13:13-0400

F=GmMR2F =G\frac{mM}{R^2}

for a mass of 1 kg on the ground:\text{for a mass of 1 kg on the ground:}

F1=10NF_1 = 10N

R1=600km=6105mR_1=600km=6*10^5m

F1=GM(6105)2F_1=G\frac{M}{(6*10^5)^2}


for a mass of 8 kg at a distance of 2000 km\text{for a mass of 8 kg at a distance of 2000 km}

from the center of the earth:\text{from the center of the earth:}

R2=2000km=2106mR_2= 2000km = 2*10^6m

F2=G8M(2106)2F_2=G\frac{8M}{(2*10^6)^2}

F2=8F1(6105)2(2106)2=7.2NF_2=8F_1\frac{(6*10^5)^2}{(2*10^6)^2}=7.2N


Answer:7.2N\text{Answer:}7.2N


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