A bullet weighing 4.5*10^-3 kg is fixed horizontally into a 1.8 kg wooden block at rest on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet comes to rest in the block which moves 1.8m. Find the speed of the bullet.
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Expert's answer
2021-09-08T08:14:11-0400
Given:
m=4.5∗10−3kg
M=1.8kg
μ=0.20
d=1.8m
Let the initial speed of the bullet we denoted as u.Then initial speed of the block is given by the law of conservation of momentum
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