Question #216080

Two crossed belts on pulleys of diameters 3.6 m and 2.4 m connect two parallel shafts with centres 4.2 meters apart. The maximum tension in the belts is limited to 1200 N and friction between the belts and the pulley, μ = 0.26. The smaller pulley has a speed of 300 rev/min.

2.1. Find the power that can be transmitted. (8)

2.2. What would be transmitted if open belts were used. (8)


1
Expert's answer
2021-07-13T10:42:08-0400

1)

P1=μFlνd2d1=9.8 kW,P_1=\mu F l\nu\frac {d_2}{d_1}=9.8~kW,

2)

P2=P1d12d22=4.4 kW.P_2=P_1\frac{d_1^2}{d_2^2}=4.4~kW.


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