Question #186216

A trough of length 6 ft has for its vertical cross section an isosceles trapezoid. The upper and lower bases are 6 ft and 2 ft respectively and the altitude is 2 ft. If the trough is full of water, find the force on the slant side of the trough.


1
Expert's answer
2021-04-29T07:28:21-0400

Given:

b = 2 ft = 0.61 m;

h = 2 ft = 0.61 m;

w = 6 ft = 1.83 m;

l = 6 ft = 1.83 m.

Find the force perpendicular to the vertical plane equal to the slant side in height and width:

Fp=12ρgh(hw)=1210009.80.61(1.830.61)==3320 N.F_p=\frac12\rho gh(hw)=\frac12·1000·9.8·0.61(1.83·0.61)=\\=3320\text{ N}.

Find the volume above the slant:


V=14(wb)hl=0.34 m3.V=\frac14 (w-b)hl=0.34\text{ m}^3.

The weight of water above the slant side:


w=Vρg=3330 N.w=V\rho g= 3330\text{ N}.

The magnitude of the force is


R=w2+Fp2=4700 N.R=\sqrt{w^2+F_p^2}=4700\text{ N}.


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