A trough of length 6 ft has for its vertical cross section an isosceles trapezoid. The upper and lower bases are 6 ft and 2 ft respectively and the altitude is 2 ft. If the trough is full of water, find the force on the slant side of the trough.
Given:
b = 2 ft = 0.61 m;
h = 2 ft = 0.61 m;
w = 6 ft = 1.83 m;
l = 6 ft = 1.83 m.
Find the force perpendicular to the vertical plane equal to the slant side in height and width:
"F_p=\\frac12\\rho gh(hw)=\\frac12\u00b71000\u00b79.8\u00b70.61(1.83\u00b70.61)=\\\\=3320\\text{ N}."
Find the volume above the slant:
The weight of water above the slant side:
The magnitude of the force is
Comments
Leave a comment