Answer to Question #186165 in Classical Mechanics for Jessica Vumba

Question

X=5t^2 - 2t. Find the velocity at t=3s

tX=5

Answer 1

$x(t) = 5t^2-2t;$

$V(t) = x'(t)= 10t-2;$

$V(3)= 10*3-2 = 28$

$V(5) = 10*5 -2 = 48$

$Answer: V(3) = 28;V(5) =48$