Question #177443

A box is pulled on level ground by a force of 40 N that makes 45° with the ground.


Find a) the force that tends to lift the box, and b) the force that tends to pull the box forward.


Expert's answer

expand the force F into vertical and horizontal projections\text{expand the force F into vertical and horizontal projections}

F⃗=F⃗∗cos⁡α+F⃗∗sin⁡α\vec{F}= \vec{F}*\cos\alpha+\vec{F}*\sin\alpha

a) the force that tends to lift the box is F⃗∗cos⁡α=40∗12≈28.3J\text{a) the force that tends to lift the box is } \vec{F}*\cos\alpha= 40*\frac{1}{\sqrt2}\approx28.3 J

b) the force that tends to pull the box forward isF⃗∗sin⁡α=40∗12≈28.3J\text{b) the force that tends to pull the box forward is}\vec{F}*\sin\alpha= 40*\frac{1}{\sqrt2}\approx28.3 J

Answer:a) 28.3J b) 28.3J


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