Question #165288

A baseball pitcher throws a fastball at a speed of 40.25 m/s (90. mph). The acceleration occurs as the pitcher holds the ball in his hand and moves through an almost straight-line distance of 3.40 m. Assuming that the acceleration is uniform, determine the acceleration. Compare the acceleration to the acceleration due to gravity (ratio or ‘G force’). 


Expert's answer

Answer

Accelaration is given by

a=vf2vi22d=(40.25)202×3.4=236.24m/s2a=\frac{v_f^2-v_i^2}{2d}=\frac{(40.25)^2-0}{2\times3.4}\\=236.24m/s^2


Now compare to gravity

ag=236.249.8=24.31\frac{a}{g}=\frac{236.24}{9.8}=24.31






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