An object of mass 10 kg is whirled round a horizontal circle of radius 4m by a revolving string inclined to the vertical. If the uniform speed of the object is 5m/s, calculate
1. The tension in the string and the angle of inclination of the string to the vertical
1
Expert's answer
2021-02-15T07:47:38-0500
forces acting on an object:
Fg−gravity
Fg=mg=9.8∗10=98N
Fc−force centripetal acceleration
Fc=ma;a=Rv2=425=6.25m/s2
Fc=10∗6.25=62.5N
T−string tension
X-axis projection
Tx+Fg=0
∣Tx∣=Fg=98N
Y-axis projection
Ty=Fc
Ty=62.5N
T=Tx2+Ty2=62.52+982≈116.23N
α−angle of inclination of the string to the vertical
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