Show the energy consideration of harmonic oscillator at any time t and show that the energy decreases exponentially at a faster rate , E(t)= E0e-2βt where E0= 1/2KA2
Answer
harmonic oscillator differential equation is given by
"\\frac{md^2x}{dt^2}+kx=0"
Solution of above euation can be calculated by differential equation
Which is found
"x=Ae^{-\\beta t}"
Differentiate with respect to t
"v=\\frac{dx}{dt}=-A\\beta e ^{-\\beta t}"
the energy consideration of harmonic oscillator at any time t is given by
"E=\\frac{mv^2}{2}"
Putting value of velocity
"E=\\frac{e^{-2\\beta t}}{2KA^2}=E_0e^{-2\\beta t}"
Where
"E_0= 1\/2KA^2"
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