Answer to Question #154375 in Classical Mechanics for John smith

Question #154375

A golf club with 70j of energy strikes a stationary golf ball with a mass of 48.0 g. The energy transfer is only 21% efficientCalculate the initial speed of the golf ball. 


1
Expert's answer
2021-01-12T12:13:37-0500

Let's first find the kinetic energy transfered to golf ball:


KEball=0.21KEgolf club=0.2170 J=14.7 J.KE_{ball}=0.21KE_{golf\ club}=0.21\cdot70\ J=14.7\ J.

Finally, we can find the initial speed of the golf ball after the hitting by the golf club:


KEball=12mv2,KE_{ball}=\dfrac{1}{2}mv^2,v=2KEballm=214.7 J4.8102 kg=24.75 ms.v=\sqrt{\dfrac{2KE_{ball}}{m}}=\sqrt{\dfrac{2\cdot 14.7\ J}{4.8\cdot10^{-2}\ kg}}=24.75\ \dfrac{m}{s}.

Answer:

v=24.75 ms.v=24.75\ \dfrac{m}{s}.


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