A plane flies east at 400m/s and them accelerates west at 6.0m/s^2 for 5 seconds. Determine the distance traveled during the 5 seconds.
Answer
Using newton second equation of motion
s=ut+1/2at2s=ut+1/2at^2s=ut+1/2at2
s=400×5+0.5×6×5×5=2075ms=400\times5+0.5 \times6 \times5\times5\\=2075ms=400×5+0.5×6×5×5=2075m
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