Question #122771

A stone of mass $10$g placed at the top of a tower $50$m high is allowed to fall freely. Show that law of conservation of energy is holds.

Expert's answer

Given, Mass of stone is M=10gM=10g ,Height of the tower is H=50mH=50m .


Initially, energy on system is just form of potential in particularly gravitional potential energy,thus


E=MgHE=MgH

Now, consider at any arbitrary time ,the stone reach to distance XX and velocity is vv ,thus kinetic energy at that moment is

K=12Mv2K=\frac{1}{2}Mv^2

Potential energy is

U=Mg(H−X)U=Mg(H-X)

Also, due to free fall under gravity

v2=2gXv^2=2gX

Hence, considering the above fact energy on the system will be

K+U  ⟹  K+U=MgH=EK+U\\ \implies K+ U=MgH=E

We are done.


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