Question #101675

A body of mass 12kg is projected vertically upwards and made a trajectory with base length 8m for 3secs when the body us projected vertically downwards it droped into a cylinder containing a liquid of relative density 0.92 if the distance traveled by the body vertically downwards is given as y = 3t4-4t3-8)m

Find the weight of the body

Density of the body


Expert's answer

Given that mass of the object = 12kg

weight of the body=mg= mg

a) weight of the body =12×9.8=117.6N=12\times 9.8=117.6N


Now,

Drag force due to liquid

y=3t44t38y=3t^4−4t^3−8

d2ydx2=36t224t\dfrac{d^2y}{dx^2}=36t^2-24t

The equation written in the last line is not clear, kindly provide the correct data, so that i can provide you the resolution.


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