Question #88621

a beta particle of energy 1MeV enters a thin window detector tube filled with methane and organ and initiates an avalanche of 5×10^10 Ion pairs the average energy lose per ion pair creation is 50 eV. the multiplication factor is

Expert's answer

the multiplication factor is equal to


50×1010×501×106=2.5×107\frac {50 \times 10^{10} \times 50} {1\times 10^6} =2.5 \times 10^7


Answer:

2.5×1072.5 \times 10^7


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