Question #88619
500 alpha particles of energy 5 MeV enter ionization chamber per second the energy required for ion pair creation is 25 eV. the ionization currently produced is
1)1.6×10^-11
2)9×10^-11
1
Expert's answer
2019-04-30T09:52:22-0400

Number of pairs per second is equal


n=500×5×10625×1s=108pairs/s(1)n=\frac {500 \times 5 \times 10^6 } {25} \times 1 s =10^8 pairs/ s (1)

Electric current


i=108pairs/s×1.6×1019C×1s=1.6×1011Ci=10^8 pairs/ s \times1.6 \times 10^{-19} C \times 1 s = 1.6 \times 10^{-11} C

Answer:

1.6×1011C1.6 \times 10^{-11} C


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