What is the coefficient of kinetic friction between the 100 N and 39 ⁰
Incomplete question.
With the given data, we can frame the question like this:
A 100 kg box is at rest on a horizontal table. The force of 100 N is required to move the box at constant speed. Determine the coefficient of kinetic friction between the box and the table.
Solution:
Given: mass (m)=100 kg
Force (F)=100 N and acceleration due to gravity (g)=10 "m\/s^2"
Now we know that "F=u_{k} m g"
"100 =u_{k} \\times 100 \\times 10\\\\\n\n\\therefore u_{k}=\\frac{100}{1000} \\\\\n\nu_{k}=0.10"
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