Answer to Question #259990 in Atomic and Nuclear Physics for Dom

Question

what is the magnitude of the electrostatic force between two electrons separated by a distance of 1.00 X 10-8 meter?

Answer 1

The magnitude of the electrostatic force between two electrons is given as follows:

$F = k\dfrac{e^2}{r^2}$

where $k = 8.99\times 10^9Nm^2/C^2$ is the Coulomb constant, $e = 1.6\times 10^{-19}C$ is the charge of electron, $r = 10^{-8}m$ is the distance between electrons. Thus, obtain:

$F = 8.99\times 10^9\dfrac{(1.6\times 10^{-19})^2}{(10^{-8})^2} \approx 2.30\times 10^{-12}N$

Answer. $2.30\times 10^{-12}N$.