Answer to Question #206428 in Atomic and Nuclear Physics for Nick

Question

How many 5 MeV alpha particles are required to deposit a total energy of 1 J?

Answer 1

First, remember what 1 MeV is: 1,000,000 eV. What is 1 eV? The energy required to move an electrons of elementary charge e in the potential of 1 V:

1 eV is 1.609·10^-19·1=1.609·10^-19 J. Therefore:

$$N=\frac{1}{5000000·1.609·10^{-19}}=1.25·10^{12}.$$