Answer to Question #162068 in Atomic and Nuclear Physics for Misbah

Question #162068

7: find wavenumber, wavelength and frequency of Ha line of Hydrogen, assuming that the nucleus has infinite mass. Calculate the wavelength of the Balmer series limit.


1
Expert's answer
2021-02-16T10:11:58-0500

Wave number is reciprocal of wavelength i.e. number of wavelength per centimeter. It is denoted by vˉ\bar{v}. H-alpha (Hα​) is a specific deep-red visible spectral line in the Balmer series; it occurs when a hydrogen electron falls from its third to second lowest energy level. For Hα​ - line in Balmer series of hydrogen spectrum vˉ\bar{v} is given by vˉ\bar{v} = R[122\frac{1}{2^2} - 132\frac{1}{3^2} ] = 5R36\frac{5R}{36} = 1.52 ×\times 106, where R is Rydberg constant.


Wavelength =1wawe\frac{1}{wawe №} = 656.28 nm.


Frequency:

ΔE = hf = −13.6(1914\frac{1}{9} - \frac{1}{4}) eV

ΔE = (13.6 ×\times 5 / 36) ×\times 1.6 ×\times 10−19 J

f = ΔEh\frac{ΔE}{h} ​= 13.6×5×1.6×101936×6.6×1034\frac{13.6 \times 5 \times 1.6 \times 10−19}{36 \times 6.6 \times 10−34} = 4.57 ×\times 1014 Hz


For series limit of Balmer series,

p = 2 and n = ∞

\frac{}{}1λ\frac{1}{ λ} = R(1p21n2\frac{1}{p^2}-\frac{1}{n^2}) = R(141\frac{1}{4} - \frac{1}{∞})

∴λ = 4R\frac{4}{R}

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