Answer to Question #160690 in Atomic and Nuclear Physics for bahgat

Question

When an evacuated container whose volume is 600 mL is filled with O2 gas at 40°C and 900 mmHg, the mass of the container will increase by …………………g 

Answer 1

T = 40 +273 = 313 K

V = 600 mL = 0.6 L

p = 900 mmHg = 1.18 atm

Ideal Gas Law

pV = nRT

R = 0.08206 L×atm/mol×K

$n = \frac{pV}{RT} \\ = \frac{1.18 \times 0.6}{0.08206 \times 313} \\ = 0.0275 \;mol \\ M(O_2) = 32 g/mol \\ m(O_2) = n \times M \\ = 0.0275 \times 32 \\ = 0.88 \;g$

The mass of the container will increase by 0.88 g.