According to Beer-Lambert law,
I=I0e−μz=I0e−μρλ=I0e−αλI = I_0 e^{-\mu z} = I_0 e^{-\frac{\mu}{\rho}\lambda} = I_0 e^{-\alpha \lambda}I=I0e−μz=I0e−ρμλ=I0e−αλ
where III is intensity, μ\muμ - linear attenuation coefficient, α\alphaα - mass attenuation coefficient, λ=ρl\lambda = \rho lλ=ρl - the area density known also as mass thickness.
So, α=μρ\displaystyle \alpha = \frac{\mu}{\rho}α=ρμ.
Answer: α=μρ\displaystyle \alpha = \frac{\mu}{\rho}α=ρμ .
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Thank you so much for helping me, you have truly solved my problems. Thank you once again