Answer to Question #118557 in Atomic and Nuclear Physics for Alhassan Moammed

Question #118557
A radioactive material A (decay constant ΠA) decays into a material B (decay constant ΠB) and then into C(decay constant ΠC) which is also radioactive. Determine the amount of C remaining after a time t.
1
Expert's answer
2020-05-28T11:48:45-0400

A(ПА)B(ПА)C(ПА)A (ПА)\to B(ПА)\to C(ПА)


NA(t)=NA0eПАtN_A(t)=N_{A0}e^{-ПА\cdot t}


NВ0=NA0NA(t)=NA0NA0eПАt=NA0(1eПАt)N_{В0}=N_{A0}-N_A(t)=N_{A0}-N_{A0}e^{-ПА\cdot t}=N_{A0}(1-e^{-ПА\cdot t})


NВ(t)=NB0eПВt=NA0(1eПАt)eПВtN_В(t)=N_{B0}e^{-ПВ\cdot t}=N_{A0}(1-e^{-ПА\cdot t})\cdot e^{-ПВ\cdot t}


NС(t)=NС0eПСtN_С(t)=N_{С0}e^{-ПС\cdot t}


NС0=NВ0NВ(t)=NA0(1eПАt)NA0(1eПАt)eПВt=N_{С0}=N_{В0}-N_В(t)=N_{A0}(1-e^{-ПА\cdot t})-N_{A0}(1-e^{-ПА\cdot t})e^{-ПВ\cdot t}=


=NA0(1eПАt)(1eПВt)=N_{A0}(1-e^{-ПА\cdot t})\cdot (1-e^{-ПВ\cdot t})


NС(t)=NС0eПСt=NA0(1eПАt)(1eПВt)eПСtN_С(t)=N_{С0}e^{-ПС\cdot t}=N_{A0}(1-e^{-ПА\cdot t})\cdot (1-e^{-ПВ\cdot t})e^{-ПС\cdot t}


NС(t)NA0=(1eПАt)(1eПВt)eПСt\frac{N_С(t)}{N_{A0}}=(1-e^{-ПА\cdot t})\cdot (1-e^{-ПВ\cdot t})e^{-ПС\cdot t} Answer





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