Electron configuration of Boron is Z=1s22s22p1Z=1s^22s^22p^1Z=1s22s22p1
For ground state2p1,s=12and2p^1, s=\frac{1}{2} and2p1,s=21and l=1l=1l=1
The possible value of J is J=l+s=1+12=32J=l+s=1+\frac{1}{2}=\frac{3}{2}J=l+s=1+21=23
And L=l=1,L=1L=l=1 ,L=1L=l=1,L=1 this means L=PL=PL=P
Spectroscopic term symbol formula is
2s+1LJ=(2(12)+1)L32=2P32^{2s+1}L_J=^{(2(\frac{1}{2})+1)}L_\frac{3}{2}=^2P_\frac{3}{2}2s+1LJ=(2(21)+1)L23=2P23
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