Question #105875

The driver of a car suddenly applies the brakes hard for 2.6 s. As a result, an average force of 6200 N is exerted on the car to slow it. What is the impulse on the car?

Expert's answer

According to the second Newton's low


F=ΔpΔtΔp=FΔt=62002.6=16120F=\frac{\Delta p}{\Delta t}\to\Delta p=F\cdot\Delta t=6200\cdot2.6=16120 kgms\frac{kg\cdot m}{s}


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