2020-02-15T11:04:08-05:00
For Kepler's period law, what is the relation if T and R is respectively the period of revolution of the planet about the sun and distance of the planet from the sun?
1
2020-02-17T09:19:07-0500
For Kepler's period law
T 2 R 3 = 4 π 2 G M S \frac{T^2}{R^3}=\frac{4\pi^2}{GM_S} R 3 T 2 = G M S 4 π 2
T 2 R 3 = 4 π 2 ( 6.67 ⋅ 1 0 − 11 ) ( 1.99 ⋅ 1 0 30 ) = 2.97 ⋅ 1 0 − 19 s 2 m 3 \frac{T^2}{R^3}=\frac{4\pi^2}{(6.67\cdot 10^{-11})(1.99\cdot 10^{30})}=2.97\cdot 10^{-19}\frac{s^2}{m^3} R 3 T 2 = ( 6.67 ⋅ 1 0 − 11 ) ( 1.99 ⋅ 1 0 30 ) 4 π 2 = 2.97 ⋅ 1 0 − 19 m 3 s 2
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