Answer to Question #120339 in Philosophy for nina

Question

By using only basic rules of QL and SL, prove the following:
a. ∃x¬Px ∴ ¬∀xPx
b. ∅ ∴ ∀x¬Px → ¬∃xPx
c. ∃x (Px & ∀y (Py → y=x)) ∴ ∀x∀y ((Px & Py) → x=y)
d. ∃x (Fx & ∀y (Fy → x=y)) ∴ ∃xFx & ∀x∀y((Fx & Fy) → y=x)

Answer 1

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