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Trigonometry
Please verify this identity on your own paper and upload a picture of your work.
tan(θ)+cot(θ)=sec(θ)csc(θ)
tan(θ)+cot(θ)=sec(θ)csc(θ)
Trigonometry
To show that sin^2x+cos^2x=1 is equivalent to tan^2x+1=sec^2x,
what do you need divide sin^2x+cos^2x=1 by?
what do you need divide sin^2x+cos^2x=1 by?
Trigonometry
Which expression is equivalent to
(sin(θ)+cos(θ))^2?
(sin(θ)+cos(θ))^2?
Trigonometry
cos^2(θ)tan^2(θ)
Trigonometry
If sec(α)<0 and the sin(α)=15/17
What is the exact value of cot(α)
What is the exact value of cot(α)
Trigonometry
If sec(α)<0 and sin(α)=15/17,
what quadrant is the terminal side of α in?
what quadrant is the terminal side of α in?
Trigonometry
cos(15°) can be evaluated using a sum or difference trig identity. Which of the following is equivalent to cos(15°)?
Trigonometry
csc^2(x)−cot^2(x)=
Trigonometry
sec(x)(sec(x)−cos(x))=
Trigonometry
Garett is attempting to verify this trig identity. He makes a mistake on one of the lines below. Which line has his first mistake?
sec(θ)−sin(θ)tan(θ)=cos(θ)
1.1cos(θ)−sin(θ)1(sin(θ)cos(θ))=cos(θ)
2. 1cos(θ)−sin(θ)cos(θ)=cos(θ)
3. 1−sin(θ)cos(θ)=cos(θ)
4. cos(θ)=cos(θ)
sec(θ)−sin(θ)tan(θ)=cos(θ)
1.1cos(θ)−sin(θ)1(sin(θ)cos(θ))=cos(θ)
2. 1cos(θ)−sin(θ)cos(θ)=cos(θ)
3. 1−sin(θ)cos(θ)=cos(θ)
4. cos(θ)=cos(θ)
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#339914 on Dec 2023
#339914 on Dec 2023